Problem of the Day
A new programming or logic puzzle every Mon-Fri

Today's problem is going to bring us back the old school. Create a function that takes in an integer N, and outputs a multiplication table for N. Here's an example with N = 12.

   1   2   3   4   5   6   7   8   9  10  11  12
   2   4   6   8  10  12  14  16  18  20  22  24
   3   6   9  12  15  18  21  24  27  30  33  36
   4   8  12  16  20  24  28  32  36  40  44  48
   5  10  15  20  25  30  35  40  45  50  55  60
   6  12  18  24  30  36  42  48  54  60  66  72
   7  14  21  28  35  42  49  56  63  70  77  84
   8  16  24  32  40  48  56  64  72  80  88  96
   9  18  27  36  45  54  63  72  81  90  99 108
  10  20  30  40  50  60  70  80  90 100 110 120
  11  22  33  44  55  66  77  88  99 110 121 132
  12  24  36  48  60  72  84  96 108 120 132 144

For bonus points make sure numbers are right aligned in their columns.

Comments:

• MintJoint - 8 years, 11 months ago

  Quick C#. This implementation aligns numbers from left rather than right but it still works.

              int num = 2;
              num = Convert.ToInt32(Console.ReadLine()); // User Input Interger N
  
              for (int i = 1; i <= num; i++)
              {
                  for (int j = 1; j <= num; j++)
                  {
                      if (j*i > 0 && j*i < 10) // One digit ints
                          Console.Write(j * i + "   ");
  
                      else if (j*i > 9 && j*i < 100) // Two digit ints
                          Console.Write(j * i + "  ");
  
                      else if (j*i > 99)  // Three digit ints
                          Console.Write(j * i + " ");
                  }
                  Console.Write('\n');
              }
  

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• Anonymous - 8 years, 11 months ago

  a = int(raw_input("Enter a number> "))
  
  row = 1
  
  rows = []
  for i in range(a):
      rows.append(i+1)
  
  count = 1
  while count <= a:
  
      timestable = [x * count for x in rows] 
      for p in timestable:
          print "%3s" % p +"\t",
      print "\n"
      count = count + 1
  

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