Problem of the Day
A new programming or logic puzzle every Mon-Fri

Comments:

• Akshay Bist - 9 years ago

  Assuming only positive integers will be passed

  def leadingDigit(num):
      while (num >= 10):
          num /= 10
      return num
  

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• Tibor - 9 years ago

  Using logarithms instead of loops (Pascal)

  The floating point operations might eat your hamster below.

  function LeadingDigit(AValue: integer): integer;
  begin
    AValue := Abs(AValue);
    if AValue = 0 then Result := 0
    else begin
      Result := AValue div Round(Power(10, Floor(Log10(AValue))));
      if Result = 10 then Result := 1;
    end;
  end;
  

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• Anonymous - 9 years ago

  #python 2.7
  import math
  
  x = int(raw_input("Enter an Integer> "))
  
  y = int(math.floor(x/math.pow(10, math.floor(math.log10(x)))))
  
  print y
  

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• k4rtik - 9 years ago

  A tiny Python function, assuming correct inputs, almost too easy:

  def leading(N):
      while N/10 > 0:
          N = N/10
      return N
  

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