Problem of the Day
A new programming or logic puzzle every Mon-Fri

Your goal for today is to write a program that asks a user for their birth year encoded as two digits (eg "90") and for the current year, also encoded as two digits (eg "14"). The program should then write out the user's age in years. Example input/output:

Year of Birth: 90
Current year: 14
Your age: 24

Comments:

• keemz - 12 years, 1 month ago

  
  print 'year of birth:'
  byear = raw_input()
  print 'current year:'
  curyear = raw_input()
  
  
  if curyear < byear:
          curyear = (int) ('2' + curyear)
  else:
          curyear = (int) ('1' + curyear)
  
  byear = (int) ('1' + byear)
  
  age = curyear - byear
  print 'your age: ' + str(age)
  
  

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• keemz - 12 years, 1 month ago

  
  if curyear < byear:
      curyear = 200 + int(curyear)
  else:
      curyear = 100 + int(curyear) 
  byear = 100 + int(byear)
  
  

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• lash - 12 years, 1 month ago

  Here is my solution in Java:

  public class Main {
      public static void main(String[] args) {
          int age;
          Scanner s = new Scanner(System.in);
          System.out.println("When were you born?");
          int birth = s.nextInt();
          System.out.println("What is the current year?");
          int current = s.nextInt();
          s.close();
          if(birth < current){
              //born post 2k
              age = current - birth;
          }else{
              int pre2k = 100 - birth;
              int post2k = current;
              age = pre2k + post2k;
          }
          System.out.println("You are " + age + " years old.");
      }
  }
  

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• lashW - 12 years, 1 month ago

  Oh and obviously it should have:

  import java.util.Scanner;
  

  at the top :)

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• Anonymous - 12 years, 1 month ago

  c# ``` var birth = 0; var current = 0;

      Console.WriteLine("2 digit birth year?");
      while( !int.TryParse(Console.ReadLine(), out birth) || Math.Floor(Math.Log10(birth) + 1) != 2)
          continue;
  
      Console.WriteLine("2 digit current year?");
      while(!int.TryParse(Console.ReadLine(), out current) || Math.Floor(Math.Log10(current) + 1) != 2)
          continue;
  
      Console.WriteLine(current - birth < 0 ? current-birth+100 : current - birth);
  

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• Emre Ozdemir - 12 years, 1 month ago

  #include <iostream>
  using namespace std;
  int main (void){
      int born, current;
      cout<<"Year of birth: ";
      cin>>born;
      cout<<"Current year: ";
      cin>>current;
      cout<<"Your age: "<<current-born+100;
      getchar();
      getchar();
  }
  

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• Will - 12 years, 1 month ago

  Easy-peasy lemon squeezy in LISP!

  (defun find-age-helper (birth-year this-year)
    (+ (- 100 birth-year) this-year))
  
  (defun find-age ()
    (let ((birth-year 0)
      (current-year 0))
      (format t "Year of Birth: ")
      (setf birth-year (read))
      (format t "Current year: ")
      (setf current-year (read))
      (format t "Your age: ~D" (find-age-helper birth-year current-year))))
  

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• Pearce Keesling - 12 years, 1 month ago

  As far as I can tell this is probably the most efficient way to do this (there might be little tweaks, but I mean the general idea). Wrote this up in C++.

  #include <iostream>
  
  using namespace std;
  int main()
  {
      int birth;
      cout << "Year of birth: ";
      cin >> birth;
      int curr;
      cout << "Current Year: ";
      cin >> curr;
      int res = curr - birth;
      cout << "Your age: " << res+(res < 0?100:0)<<endl;
      return 0;
  }
  

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• brocksrockgym - 12 years, 1 month ago

  import java.util.Scanner;
  public class Y2K
  {
      public static void main(String[] args)
      {
          Scanner in = new Scanner(System.in);
          int yearBorn = 0;
          int currentYear = 0;
  
          System.out.print("Year born: ");
          yearBorn = in.nextInt();
          System.out.print("Current year: ");
          currentYear = in.nextInt();
          if(yearBorn <= currentYear)
              yearBorn += 100;
          System.out.println("Current age: " + (((currentYear+100)-yearBorn)));
      }
  }
  

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• rossthebossperot - 11 years, 7 months ago

  Some Python

  def agefinder(birth,current):
      age = 0
      age = (100 - int(birth)) + int(current)
      return(age)
  
  yourage = agefinder(input('Last 2 digits of your birth year:'),input('Last 2 digits of current year:'))
  
  print('You are',yourage,'Years old.')
  

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• rossthebossperot - 11 years, 7 months ago

  And a one liner for good measure

  print('You are',(100-(int(input('Birth year:')))) + (int(input('Current year:'))))
  

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